探究題:觀察下列各式的變化規(guī)律,然后解答下列問(wèn)題:11×2=1-12,12×3=12-13,13×4=13-14,14×5=14-15….
(1)計(jì)算:若n為正整數(shù),猜想1n(n+1)=1n-1n+11n-1n+1;
(2)1x+2023+1x(x+1)+1(x+1)(x+2)+?+1(x+2022)(x+2023);
(3)若|ab-2|+|b-1|=0,求1ab+1(a+1)(b+1)+1(a+2)(b+2)+…+1(a+21)( b+21)的值.
1
1
×
2
=
1
-
1
2
,
1
2
×
3
1
2
-
1
3
1
3
×
4
=
1
3
-
1
4
1
4
×
5
=
1
4
-
1
5
1
n
(
n
+
1
)
1
n
1
n
+
1
1
n
1
n
+
1
1
x
+
2023
+
1
x
(
x
+
1
)
+
1
(
x
+
1
)
(
x
+
2
)
+
?
+
1
(
x
+
2022
)
(
x
+
2023
)
1
ab
+
1
(
a
+
1
)
(
b
+
1
)
+
1
(
a
+
2
)
(
b
+
2
)
+
…
+
1
(
a
+
21
)
(
b
+
21
)
【答案】-
1
n
1
n
+
1
【解答】
【點(diǎn)評(píng)】
聲明:本試題解析著作權(quán)屬菁優(yōu)網(wǎng)所有,未經(jīng)書(shū)面同意,不得復(fù)制發(fā)布。
發(fā)布:2024/10/16 4:0:1組卷:80引用:5難度:0.7
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3.觀察下列各等式:
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