已知數(shù)列{an}滿足a1+2a2+…+(n-1)an-1+nan=n2(n∈N*).
(1)求數(shù)列{an}的通項(xiàng)公式an;
(2)數(shù)列{bn}滿足bn=(12)n?n?an,數(shù)列{bn}的前n項(xiàng)和為Tn,若不等式λ<Tn對(duì)一切n∈N*恒成立,求λ的取值范圍.
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【考點(diǎn)】錯(cuò)位相減法.
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發(fā)布:2024/4/20 14:35:0組卷:74引用:2難度:0.5
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