設(shè)函數(shù)f1(x)=x2+aex(其中a為非零常數(shù),e是自然對(duì)數(shù)的底),記fn(x)=fn-1′(x)(n≥2,n∈N*).
(1)求對(duì)任意實(shí)數(shù)x,都有fn(x)=fn-1(x)成立的最小整數(shù)n的值(n≥2,n∈N*);
(2)設(shè)函數(shù)gn(x)=f2(x)+f3(x)+?fn(x),若對(duì)任意n≥3,n∈N*,y=gn(x)存在極值點(diǎn)x=tn,求證:點(diǎn)An(tn,gn(tn))(n≥3,n∈N*)在一定直線上,并求該定直線方程;
(3)是否存在正整數(shù)k(k≥2)和實(shí)數(shù)x0,使fk(x0)=fk-1(x0)=0,且對(duì)任意的正整數(shù)n,fn(x)至多有一個(gè)極值點(diǎn),若存在,求出所有滿足條件的k和x0,若不存在,說(shuō)明理由.
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【考點(diǎn)】利用導(dǎo)數(shù)研究函數(shù)的極值;數(shù)列與函數(shù)的綜合.
【答案】(1)nmin=5;(2)證明見解析;An(tn,gn(tn))在直線y=2x上;(3).
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【解答】
【點(diǎn)評(píng)】
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發(fā)布:2024/6/27 10:35:59組卷:326引用:6難度:0.2
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